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Two circuits have coefficient of mutual induction of `0.09` henry. Average e.m.f. induced in the secondary by a change of current from `0` to `20` ampere in `0.006` second in the primary will be

A

`120 V`

B

`80 V`

C

`200 V`

D

`300 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`e=M(di)/(dt)=0.09xx(20)/(0.006)=300 V`
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