When current in a coil changes to 2 ampe...

When current in a coil changes to `2` ampere from `8` ampere in `3xx10^(-3)`, the e.m.f. induced in the coil is `2` volt. The self-inductance of the coil in millihenry is

`1`

`5`

`20`

`10`

Text Solution

Verified by Experts

The correct Answer is:

`e=L(di)/(dt)implies2=Lxx(6)/(3xx10^(-3))impliesL=1 mH`

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