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In a coil of self-inuctance 0.5 henry, t...

In a coil of self-inuctance `0.5` henry, the current varies at a constant rate from zero to `10` amperes in `2` seconds. The e.m.f. generated in the coil is

A

`10` volts

B

`5` volts

C

`2.5` volts

D

`1.25` volts

Text Solution

Verified by Experts

The correct Answer is:
C
`(Deltai)/(Deltat)=(10)/(2)=5 A//secimpliese=L(Deltai)/(Deltat)=0.5xx5=2.5` volts
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