If the current is halved in a coil, then the energy stored is how much times the previous value

Options

A. `(1)/(2)`
B. `(1)/(4)`
C. `2`
D. `4`

Answer

B

Explanation

`U=(1)/(2)Li^(2)i.e.(U_(2))/(U_(1))=((i_(2))/(i_(1)))^(2)=((1)/(2))^(2)=(1)/(4)`
`impliesU_(2)=(1)/(4)U_(1)`