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the inductance of a closed-packed coil o...

the inductance of a closed-packed coil of `400` turns is `8mH`. `A` current of `5mA` is passed through it. The magnetic flux through each turn of the coil is

A

`(1)/(4pi)mu_(0)Wb`

B

`(1)/(2pi)mu_(0)Wb`

C

`(1)/(3pi)mu_(0)Wb`

D

`0.4mu_(0)Wb`

Text Solution

Verified by Experts

The correct Answer is:
A
`Nvarphi=Liimpliesvarphi=(Li)/(N)=(8xx10^(-3)xx5xx10^(-3))/(400)`
`=10^(-7)=(mu_(0))/(4pi)wb`
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