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If in a coil rate of change of area is 5...

If in a coil rate of change of area is `5m^(2)//millisecond` and current become `1 amp` from `2 amp` in `2xx10^(-3)` sec. magnitude of field id `1 teslsa` then self-inductance of the coil is

A

`2H`

B

`5H`

C

`20H`

D

`10H`

Text Solution

Verified by Experts

The correct Answer is:
D

`Nvarphi=Liimplies(Ndvarphi)/(dt)=(Ldi)/(dt)impliesNB(dA)/(dt)=(Ldi)/(dt)`
`implies(1xx1xx5)/(10^(-3))=Lxx((2-1)/(2xx10^(-3)))impliesL=10H`
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