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A 100mH coil carries a current of 1 ampe...

A `100mH` coil carries a current of `1` ampere. Energy stored in its magnetic field is

A

`0.8J`

B

`8J`

C

`0.08J`

D

`80J`

Text Solution

Verified by Experts

The correct Answer is:
C
`U=(1)/(2)Li^(2)impliesU=(1)/(2)xx40xx10^(-3)xx(2)^(2)=0.08J`
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