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The self-induced e.m.f in a 0.1H coil wh...

The self-induced e.m.f in a `0.1H` coil when the current in it is changing at the rate of `200 ampere//second` is

A

`8xx10^(-4)V`

B

`8xx10^(-5)V`

C

`20V`

D

`125 V`

Text Solution

Verified by Experts

The correct Answer is:
C

`e=(Ldi)/(dt)impliese=0.1xx200=20V`
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