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A coil of N=100 turns carries a current ...

A coil of `N=100` turns carries a current `I=5 A` and creates a magnetic flux `varphi=10^(-5)Tm^(-2)` per turn. The value of its inductance `L` will be

A

`0.05 mH`

B

`0.10mH`

C

`0.15MH`

D

`0.20 mH`

Text Solution

Verified by Experts

The correct Answer is:
D
`Nvarphi=Liimplies100xx10^(-5)+Lxx5implies0.2H`
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