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A short magnet is allowed to fall along ...

A short magnet is allowed to fall along the axis of a horizontal metalic ring. Starting from rest, the distance fallen by the magnet in one second may be

A

`4m`

B

`5m`

C

`6m`

D

`7m`

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The correct Answer is:
To solve the problem of how far a short magnet falls in one second when allowed to fall along the axis of a horizontal metallic ring, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a short magnet falling through a horizontal metallic ring. The magnet starts from rest. 2. **Forces Acting on the Magnet**: - As the magnet falls, it will experience gravitational force acting downward, which is equal to \( mg \) (where \( m \) is the mass of the magnet and \( g \) is the acceleration due to gravity). - However, due to electromagnetic induction, the falling magnet will induce a current in the metallic ring, which creates an upward magnetic force opposing the fall of the magnet. 3. **Net Acceleration**: - Because of the opposing force from the induced current, the net acceleration \( a \) of the magnet will be less than \( g \). Therefore, we can say: \[ a < g \] - For simplicity, we can assume \( a \approx g \) for a short time, but we must remember that it will actually be less. 4. **Calculating Distance Fallen**: - The formula for distance fallen under constant acceleration is: \[ S = ut + \frac{1}{2} a t^2 \] - Since the magnet starts from rest, \( u = 0 \). Thus, the equation simplifies to: \[ S = \frac{1}{2} a t^2 \] - Substituting \( t = 1 \) second, we get: \[ S = \frac{1}{2} a (1)^2 = \frac{1}{2} a \] 5. **Estimating the Distance**: - If we assume \( g \approx 10 \, \text{m/s}^2 \), then: \[ S = \frac{1}{2} \cdot 10 = 5 \, \text{meters} \] - However, since the actual acceleration \( a \) is less than \( g \), the distance \( S \) will be less than 5 meters. 6. **Final Conclusion**: - Since the distance fallen by the magnet must be less than 5 meters, we can estimate that the distance fallen in one second could be around 4 meters or less. ### Answer: The distance fallen by the magnet in one second may be approximately **4 meters** or less.

To solve the problem of how far a short magnet falls in one second when allowed to fall along the axis of a horizontal metallic ring, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a short magnet falling through a horizontal metallic ring. The magnet starts from rest. 2. **Forces Acting on the Magnet**: ...
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