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The horizontal component of the earth's ...

The horizontal component of the earth's magnetic field at a place is `3xx10^(-4)T` and the dip is `tan^(-1)((4)/(3))`. A metal rod of length `0.25m` placed in the north -south position and is moved at a constant speed of `10cm//s` towards the east. The emf induced in the rod will be

A

zero

B

`1muV`

C

`5muV`

D

`10muV`

Text Solution

Verified by Experts

The correct Answer is:
D
Road is moving towards east, so induced emf across its end will be `e=B_(v)vl=(B_(H)"tan")vl`
`:. e=3xx10^(-4)xx(4)/(3)xx(10xx10^(-2))xx0.25=10^(-5)V=10muV`
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Knowledge Check

  • The value of horizontal component of earths magnetic field at a place is 0.35 xx 10 ^(-4)T. If the angle of dip is 60^(@), the value of vertical component of earths magnetic field is nearly

    A
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    B
    `0.2xx 10 ^(-4)T`
    C
    `0.4 xx 10 ^(-4)T`
    D
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    A
    `0.23xx10^(-4) Wb//m^(2)`
    B
    `0.46xx10^(-4) Wb//m^(2)`
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    `0.58xx10^(-4) Wb//m^(2)`
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    B
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    C
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