The horizontal component of the earth's magnetic field at a place is `3xx10^(-4)T` and the dip is `tan^(-1)((4)/(3))`. A metal rod of length `0.25m` placed in the north -south position and is moved at a constant speed of `10cm//s` towards the east. The emf induced in the rod will be

Options

A. zero
B. `1muV`
C. `5muV`
D. `10muV`

Answer

D

Explanation

Road is moving towards east, so induced emf across its end will be `e=B_(v)vl=(B_(H)"tan")vl`
`:. e=3xx10^(-4)xx(4)/(3)xx(10xx10^(-2))xx0.25=10^(-5)V=10muV`