A current of `2A` is increasing at a rate of `4A//s` through a coil of inductance `2H`. The energy stored in the inductor per unit time is

Options

A. `2J//s`
B. `1J//s`
C. `16J//s`
D. `4J//s`

Answer

C

Explanation

Potential difference across coil is `V=L(di)/(dt)`
or `V=(2)(4)=8` volt
Now energy stored per unit time
`=power=Vi`
`=(8)(2)`
`=16J//s`