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A physicist works in a laboratory where the magnetic field is `2T`. She wears a necklace enclosing area `0.01 m^(2)` in such a way that the plane of the necklace is normal to the field and is having a resistance `R=0.01Omega`. Because of power failure, the field decays to `1T` in time `10^(-3)` seconds.
The what is the total heat produced in her necklace?`(T=tesla)`

A

`10J`

B

`20J`

C

`30J`

D

`40J`

Text Solution

Verified by Experts

The correct Answer is:
A

`H=(V^(2)t)/(R )` and `V=(N(B_(2)-B_(1))Acostheta)/(t)`
`V=(1xx(1-2)xx0.01xxcos0^(@))/(10^(-3))=10V`
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