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In a series LR circuit (L=3H,R=1.5Omega)...

In a series `LR` circuit `(L=3H,R=1.5Omega)` and `DC` voltage `=1V`. Find current at `T=2` seconds.

A

`0.1A`

B

`2A`

C

`3A`

D

`0.4A`

Text Solution

Verified by Experts

The correct Answer is:
D
`tau=(L)/(R )impliestau=(3)/(1.5)=2`
`I=(e)/(R )[1-e^(-t//tau)]`
`I=(1)/(1.5)[1-e^(2//2)]`
`I=(2)/(3)[1-(1)/(e)]=0.4A`
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