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In Young's double slit experiment the am...

In Young's double slit experiment the amplitudes of two sources are `3a` and `a` respectively. The ratio of intensities of bright and dark fringes will be

A

(a) `3:1`

B

(b) `4:1`

C

(c) `2:1`

D

(d) `9:1`

Text Solution

Verified by Experts

The correct Answer is:
B
`(I_(max))/(I_(min))=((a_1+a_2)/(a_1-a_2))^2=((3a+a)/(3a-a))^2=4/1`
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Knowledge Check

  • In Young's double slit experiment, the interference bright fringes are of:

    A
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    B
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