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In Young's double slit experiment, the i...

In Young's double slit experiment, the intensity on the screen at a point where path difference is `lambda` is K. What will be the intensity at the point where path difference is `lambda//4`?

A

(a) `K/4`

B

(b) `K/2`

C

(c) `K`

D

(d) Zero

Text Solution

Verified by Experts

The correct Answer is:
B
By using phase difference `varphi=(2pi)/(lambda)(Delta)`
For path difference `lambda`, phase difference `varphi_1=2pi` and for path difference `lambda//4`, phase difference `varphi_2=pi//2`.
Also by using `I=4I_0cos^2varphi/2impliesI_1/I_2=(cos^2(varphi_1//2))/(cos^2(varphi_2//2))`
`impliesK/I_2=(cos^2(2pi//2))/(cos^2(pi//2/2))=(1)/(1//2)impliesI_2=K/2`.
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Knowledge Check

  • In Young's double slit experiment, the intensity on the screen at a pont where path difference lamda is K. what will be the intensity at the point where the path difference is lamda/4 ?

    A
    `K/4`
    B
    `K/2`
    C
    `K`
    D
    Zero

  • In a Young's double slit experiment, the central point on the screen is

    A
    Bright
    B
    Dark
    C
    First bright and then dark
    D
    First dark and then bright

  • In Young's double slit experiment the intensity of light at a point on the screen where the path difference lambda is K. The intensity of light at a point where the path difference is (lambda)/(6) [ lambda is the wavelength of light used] is

    A
    `K//4`
    B
    `K//3`
    C
    `3K//4`
    D
    `K`

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