The Young's experiment is performed with the lights of blue `(lambda=4360Å)` and green colour `(lambda=5460Å)`. If the distance of the 4th fringe from the centre is x, then

Options

A. (a) `x(Blue)=x(Green)`
B. (b) `x(Blue)gtx(Green)`
C. (c) `x(Blue )lt x(Green)`
D. (d) `(x(Blue))/(x(Green))=(5460)/(4360)`

Answer

C

Explanation

Distance of `n^(th)` bright fringe `y_n=(nlambdaD)/(d)` i.e., `y_nproplambda`
`:. (x_(n_1))/(x_(n_2))=(lambda_1)/(lambda_2)implies(x(Blue))/(x(Green))=(4360)/(5460)`
`:. x(Green)gtx(Blue)`.