If a transparent medium of refractive index `mu=1.5` and thickness `t=2.5xx10^-5m` is inserted in front of one of the slits of Young's Double Slit experiment, how much will be the shift in the interference patten? The distance between the slits is `0.5mm` and that between slits and screen is `100cm`

Options

A. (a) `5cm`
B. (b) `2.5cm`
C. (c) `0.25cm`
D. (d) `0.1cm`

Answer

B

Explanation

Shift in the fringe pattrn `x=((mu-1)t.D)/(d)`
`=((1.5-1)xx2.5xx10^-5xx100xx10^-2)/(0.5xx10^-3)=2.5cm.`