In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is `5460 Å`. Then, angular position of first dark fringe is approximately

Options

A. (a) `0.08^@`
B. (b) `0.16^@`
C. (c) `0.20^@`
D. (d) `0.313^@`

Answer

D

Explanation

Angular position of first dark fringe
`theta=(lambda)/(d)=(5460xx10^(-10))/(0.1xx10^-3)xx(180)/(pi)`(in degree)
`=0.313^@`