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In a biprism experiement, by using light...

In a biprism experiement, by using light of wavelength `5000Å`, `5mm` wide fringes are obtained on a screen `1.0m` away from the coherent sources. The separation between the two coherent sources is

A

(a) `1.0mm`

B

(b) `0.1mm`

C

(c) `0.05mm`

D

(d) `0.01mm`

Text Solution

Verified by Experts

The correct Answer is:
B
`d=(Dlambda)/(beta)=(1xx5xx10^-7)/(5xx10^-3)=10^-4m=0.1mm`.
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