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Light of wavelength 589.3nm is incident ...

Light of wavelength `589.3nm` is incident normally on the slit of width `0.1mm`. What will be the angular width of the central diffraction maximum at a distance of `1m` from the slit?

A

(a) `0.68^@`

B

(b) `1.02^@`

C

(c) `0.34^@`

D

(d) None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Angular width of central maxima`=(2lambda)/(d)`
`=(2xx589.3xx10^-9)/(0.1xx10^-3)rad=0.0117xx(180)/(pi)=0.68^@`
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