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In a diffraction pattern by a wire, on i...

In a diffraction pattern by a wire, on increasing diameter of wire, fringe width

A

(a) Decreases

B

(b) Increases

C

(c) Remains unchanged

D

(d) Increasing or decreasing will depend on wavelength

Text Solution

Verified by Experts

The correct Answer is:
A
`beta=(lambdaD)/(d)` where D=distance of screen from wire, d=diameter of wire
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