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If we observe the single slit Fraunhofer...

If we observe the single slit Fraunhofer diffraction with wavelength `lambda` and slit width d, the width of the central maxima is `2theta`. On decreasing the slit width for the same `lambda`

A

(a) `theta` increases

B

(b) `theta` remains unchanged

C

(c) `theta` decreases

D

(d) `theta` increases or decreases depending on the intensity of light

Text Solution

Verified by Experts

The correct Answer is:
A
`2theta=(2lambda)/(d)` (where d=slit width)
As d decreases, `theta` increases.
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Knowledge Check

  • If we observe the single slit Fraunhofer diffraction with wavelength lambda and slit width e , the width of the central maxima is 2 theta . On decreasing the slit width for the same lambda

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    B
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  • If we observe the single slit Fraunhofer diffraction with wavelength lambda and slit width e, the width of the central maxima is theta . On decreasing the slit width for the same lambda :

    A
    `theta` increases
    B
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  • If we observe the single slit Fraunhofer diffraction with wavelength lambda and slit width e, the width of the central maxima is theta . On decreasing the slit width for the same lambda :

    A
    `theta` increases
    B
    `theta` remains unchanged
    C
    `theta` decreases
    D
    `theta` increases or decreases depending on the intensity of light

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