If we observe the single slit Fraunhofer diffraction with wavelength `lambda` and slit width d, the width of the central maxima is `2theta`. On decreasing the slit width for the same `lambda`

Options

A. (a) `theta` increases
B. (b) `theta` remains unchanged
C. (c) `theta` decreases
D. (d) `theta` increases or decreases depending on the intensity of light

Answer

A

Explanation

`2theta=(2lambda)/(d)` (where d=slit width)
As d decreases, `theta` increases.