A screen is placed at `50cm` from a single slit, which is illuminated with `600nm` light. If separation between the first and third minima in the diffraction pattern is `3.0mm`, then width of the slit is:

Options

A. (a) `0.4mm`
B. (b) `0.1mm`
C. (c) `0.3mm`
D. (d) `0.2mm`

Answer

D

Explanation

`y_3-y_1=(3lambdax)/(alpha)-(lambdax)/(alpha)`
`implies3xx10^-3=(2xx600xx10^-9xx0.5)/(alpha)`
`=a=0.2nm`