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If in single slit diffraction pattern, f...

If in single slit diffraction pattern, first minima for red light `(600nm)` coincides with first maxima of some other wavelength `lambda`, then `lambda` would be

A

(a) `400nm`

B

(b) `440nm`

C

(c) `0.3nm`

D

(d) `900nm`

Text Solution

Verified by Experts

The correct Answer is:
A
`(3lambda)/(2alpha)=(lambda_R)/(alpha)`
`implieslambda=2/3lambda_R=2/3xx600=400nm`
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