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Two slits are separated by distance of `0.5` and illuminate with light of `lambda=6000Å`. If the screen is placed `2.5m` from the slits. The distance of the third bright image from the centre will be

A

(a) `1.5mm`

B

(b) `3mm`

C

(c) `6mm`

D

(d) `9mm`

Text Solution

Verified by Experts

The correct Answer is:
D
Distance of the nth bright fringe from the centre
`x_n=(nlambdaD)/(d)`
`impliesx_3=(3xx6000xx10^(-10)xx2.5)/(0.5xx10^-3)=9xx10^-3m=9mm`
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