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Light is incident on a polarizer with in...

Light is incident on a polarizer with intensity `I_0`. A second prism called analyzer is kept at a angle of `15^@`, from the first polarizer then the intensity of final emergent light will be

A

(a) `0.5I_0`

B

(b) `0.3I_0`

C

(c) `0.46I_0`

D

(d) `0.83I_0`

Text Solution

Verified by Experts

The correct Answer is:
C

`I=I_0/2cos^2(15^@)`
`I=I_0/4*2cos^2(15^@)`
`I=I_0/4[1+cos(30^@)]`
`I=I_0/4*[1+sqrt3/2]`
`I=I_0/8[2+sqrt3]`
`I=0.46I_0`
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