In Young's double slit experiment, the aperture screen distance is `2m`. The fringe width is `1mm`. Light of `600nm` is used. If a thin plate of glass `(mu=1.5)` of thickness `0.06mm` is placed over one of the slits, then there will be a lateral displacement of the fringes by

Options

A. (a) `0cm`
B. (b) `5cm`
C. (c) `10cm`
D. (d) `15cm`

Answer

B

Explanation

Lateral displacement of fringes `=beta/lambda(mu-1)t`
`=(1xx10^-3)/(600xx10^-9)(1.5-1)xx0.6xx10^-3`
`=1/20m=5cm`.