A sample contains `16 gm` of radioactive material, the half-life of which is two days. After `32` days, the amount of radioactive material left in the sample is

Options

A. Less than `1 mg`
B. `(1)/(4) gm`
C. `(1)/(2) gm`
D. 1 gm

Answer

A

Explanation

(a) Remaining amount
=`16 xx ((1)/(2))^(32//2) = 16 xx ((1)/(2))^16 = ((1)/(2))^12 lt 1 mg`.