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After two hours, one-sixteenth of the st...

After two hours, one-sixteenth of the starting amount if a certain radioactive isotope remained undecayed . The half-life of the isotope is

A

15 minutes

B

30 minutes

C

45 minutes

D

1 hour

Text Solution

Verified by Experts

The correct Answer is:
B

(b) `(N)/(N_0) = ((1)/(2))^(t//T) rArr ((1)/(16)) = ((1)/(2))^(2//T) rArr ((1)/(2))^4 = ((1)/(2))^(2//T)`
`rArr T = 0.5 hour = 30` minutes.
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