The half-life `(T)` and the disintegration constant `(lamda)` of a radioactive substance are related as

Options

A. `lamda T = 1`
B. `lamda T = 0.693`
C. `(T)/(lamda) = 0.693`
D. `(lamda)/(T) = 0.693`

Answer

B

Explanation

(b) By using `N = N_0 e^(- lamda t)`, we get
`(N_0)/(2) = N_0 e^(-lamda T_1//2) rArr 2 = e^(lamda T_1//2)`
By taking `log_e` both the side
`log_e 2 = lamda T_(1//2) rArr lamda T_(1//2) = 0.693`.