Half-life of a radioacitve element is `10` days. The time during which quantity remains `1//10` of initial mass will be

Options

A. 100 days
B. 50 days
C. 33 days
D. 16 days

Answer

C

Explanation

( c) After three half-lives (i.e., `30` days) it remains `((1)/(3))^3 = (1)/(8)`, so it will remain `(1)/(10)th`, approximately in `33` days.