Plutonium decays with a half-life of `24000` years. If the plutonium is stored for `72000` years, then the fraction of plutonium that remains is.

Options

A. `(1)/(2)`
B. `(1)/(3)`
C. `(1)/(4)`
D. `(1)/(8)`

Answer

D

Explanation

(d) `n = (72000)/(24000) = 3`, Now `(N)/(N_0) = ((1)/(2))^n = (1)/(8)`.