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A radioactive sample has half-life of 5 ...

A radioactive sample has half-life of `5` years. Probability of decay in `10` years will be.

A

1

B

0.75

C

0.5

D

0.25

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To solve the problem of finding the probability of decay of a radioactive sample over a period of 10 years, given its half-life of 5 years, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Half-Life Concept**: The half-life of a radioactive substance is the time required for half of the radioactive atoms in a sample to decay. In this case, the half-life (T) is given as 5 years. 2. **Determine the Time Period**: We need to find the probability of decay over a time period (t) of 10 years. 3. **Use the Decay Formula**: The fraction of undecayed particles after time t can be calculated using the formula: \[ \frac{N}{N_0} = \left(\frac{1}{2}\right)^{\frac{t}{T}} \] where \(N_0\) is the initial quantity of the substance, \(N\) is the quantity remaining after time t, and T is the half-life. 4. **Substitute the Values**: Here, \(t = 10\) years and \(T = 5\) years. Plugging these values into the formula gives: \[ \frac{N}{N_0} = \left(\frac{1}{2}\right)^{\frac{10}{5}} = \left(\frac{1}{2}\right)^{2} = \frac{1}{4} \] 5. **Calculate the Decayed Fraction**: The fraction of the sample that has decayed is given by: \[ \text{Decayed fraction} = 1 - \frac{N}{N_0} = 1 - \frac{1}{4} = \frac{3}{4} \] 6. **Convert to Percentage**: To express the decayed fraction as a percentage, multiply by 100: \[ \text{Probability of decay} = \frac{3}{4} \times 100 = 75\% \] ### Final Answer: The probability of decay in 10 years is **75%**. ---

To solve the problem of finding the probability of decay of a radioactive sample over a period of 10 years, given its half-life of 5 years, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Half-Life Concept**: The half-life of a radioactive substance is the time required for half of the radioactive atoms in a sample to decay. In this case, the half-life (T) is given as 5 years. 2. **Determine the Time Period**: ...
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