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Radioactive element decays to form a sta...

Radioactive element decays to form a stable nuclide, then the rate of decay of reactant `((d N)/(d t))` will vary with time `(t)` as shown in figure.

A

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B

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C

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D

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Text Solution

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The correct Answer is:
C
( c) `N = N_0 e^(-lamda t) rArr (dN)/(dt) = -N_0 lamda e^(-lamda t)`
i.e., Rate of decay `((dN)/(dt))` varies exponentially with time(t).
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