Home
Class 11
MATHS
12 guests at a dinner party are to be se...

12 guests at a dinner party are to be seated along a circular table. Supposing that the master and mistress of the house have fixed seats opposite to one another and that there are two specified guests who must always be placed next to one another. The number of ways in which the company can be placed, is

Promotional Banner

Similar Questions

Explore conceptually related problems

There are 12 guests at a dinner party. Supposing that the master and mistress of the house have fixed seats opposite one another, and that there are two specified guests who must always, be placed next to one another, the number of ways in which the company can be placed is

There are 2n guests at a dinner party. Supposing that the master and mistress of the house have fixed seats opposite one another , and that there are two specified guests who must not be placed next to one another. find the number of ways in which the company can be placed.

There are 2n guests at a dinner party. Supposing that eh master and mistress of the house have fixed seats opposite one another and that there are two specified guests who must not be placed next to one another,show that the number of ways in which the company can be placed is (2n-2)!xx(4n^(2)-6n+4)

There are 2n guests at a dinner party. Supposing that eh master and mistress of the house have fixed seats opposite one another and that there are two specified guests who must not be placed next to one another, show that the number of ways in which the company can be placed is (2n-2)!xx(4n^2-6n+4)dot

There are 2n guests at a dinner party. Supposing that eh master and mistress of the house have fixed seats opposite one another and that there are two specified guests who must not be placed next to one another, show that the number of ways in which the company can be placed is (2n-2!)xx(4n^2-6n+4)dot

There are 2n guests at a dinner party. Supposing that eh master and mistress of the house have fixed seats opposite one another and that there are two specified guests who must not be placed next to one another, show that the number of ways in which the company can be placed is (2n-2!)xx(4n^2-6n+4)dot

There are 2n guests at a dinner party. Supposing that eh master and mistress of the house have fixed seats opposite one another and that there are two specified guests who must not be placed next to one another, show that the number of ways in which the company can be placed is (2n-2!)xx(4n^2-6n+4)dot

Eight guests have to be seated 4 on each side of a long rectangular table.2 particular guests desire to sit on one side of the table and 3 on the other side.The number of ways in which the sitting arrangements can be made is

A man invites a party to (m+n) friends to dinner and places m at one round table and n at another. The number of ways of arranging the guests is

A man invites a party to (m+n) friends to dinner and places m at one round table and n at another. The number of ways of arranging the guests is