In the nuclear reaction : X (n, alpha)3 ...

In the nuclear reaction : `X (n, alpha)_3 Li^7` the term `X` will be `3`

`._5 B^10`

`._5 B^9`

`._5 B^11`

`._2 He^4`

Text Solution

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The correct Answer is:

(a) `X(n, alpha)._3^7 Li rArr ._ZX^A + ._0n^1 rarr 3 Li^7 +._2 He^4`
`Z = 3 + 2 = 5` and `A = 7 + 4 - 1 = 10`
`:. ._5X^10 = ._5 B^10`.

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