The binding energy of deuteron is `2.2 MeV` and that of `._2^4 He` is `28 MeV`. If two deutrons are fused to form one `._2^4 He`, then the energy released is

Options

A. `25.8 MeV`
B. `23.6 MeV`
C. `19.2 MeV`
D. `30.2 MeV`

Answer

B

Explanation

(b) The reaction can be written as
`._1 H^2 + ._1 H^2 rarr ._2 He^4 +` energy
The energy released in the reaction is difference of binding energies of daughter and parent nuclei.
Hence, energy of released
= binding energy of `._2 He^4`
`-2 xx` binding energy `._1 H^2`
`=28 -2 xx 2.2 = 23.6 MeV`.