The power obtained in a reactor using `U^235` disintegration is `100 kW`. The mas decay of `U^235` per hour is

Options

A. `20 mu g`
B. `40 mu g`
C. `1 mu g`
D. `10 mu g`

Answer

B

Explanation

(b) Let us assume power `p = 1000 W`
Energy per hour `= 1000 xx 3600 J`
Energy per fission `= 200 MeV`
=`200 xx 1.6 xx 10^-13 J`
`:.` Number of fission per hour
`n = (1000 xx 3600)/(200 xx 1.6 xx 10^-13)`
Number of mole per hour `= (n)/(N)`
`:.` Mass per hour `= (n)/(N) xx 235`
=`(1000 xx 3600 xx 235)/(200 xx 1.6 xx 10^-13 xx 6.02 xx 10^23)`
=`43.9 xx 10^-6 g`
This `43.9 xx 10^-6 g` is nearest value of `40` micron so option (b) is correct.