If the nuclear radius of `.^27 A1` is `3.6` Fermi, the approximate nuclear radius of `64 Cu` in Fermi is :

Options

A. 3.6
B. 2.4
C. 1.2
D. 4.8

Answer

D

Explanation

(d) Nuclear radius `r prop A^(1//3)`, where `A` is mass number
`r = r_0(27)^(1//3) = 3 r_0 rArr r_0 = (3.6)/(3) = 1.2 fm`
For `.^64 Cu, r = r_0 A^(1//3) = 1.2 fm (64)^(1//3) = 4.8 fm`.