If the binding energy per nucleon in L i...

If the binding energy per nucleon in `L i^7` and `He^4` nuclei are respectively `5.60 MeV` and `7.06 MeV`. Then energy of reaction `L i^7 + p rarr 2_2 He^4` is.

19.6 MeV

`-2.4 MeV`

8.4 MeV

17.3 MeV

Text Solution

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The correct Answer is:

(d) The binding energy of `._1He^4 = 4xx 7.06 = 28.14 MeV`
The binding energy of `._3^7 Li + ._1^1 H rarr ._2He^4 +._2 He^4 + Q`
`39.20 28.24 xx 2 (=56.48 MeV)`.

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