Starting with a sample of pure `.^66 Cu, 7//8` of it decays into `Zn` in `15 min`. The corresponding half-life is.

Options

A. 5 min
B. `7 (1)/(2) min`
C. 10 min
D. 15 min

Answer

A

Explanation

(a) `(7)/(8)` part decays i.e., remaining part is `r_n`
`N = N_0((1)/(2))^((t)/(T_(1//2))) rArr (1)/(8) = ((1)/(2))^((15)/(T_(1//2))) rArr T_(1//2) = 5 min`.