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Two radioactive X(1) and X(2) have decay...

Two radioactive `X_(1)` and `X_(2)` have decay constants `10 lambda ` and `lambda` respectively . If initially they have the same number of nuclei, then the ratio of the number of nuclei of `X_(1)` to that of `X_(2)`will be `1//e` after a time .

A

`1//(10 lamda)`

B

`1//(11 lamda)`

C

`11//(10 lamda)`

D

`1//(9 lamda)`

Text Solution

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The correct Answer is:
D

(d) `N_1 = N_0 e^(-10 lamda t)` and `N_2 = N_0 e^(-lamda t)`
`rArr (N_1)/(N_2) = (1)/(e) = e^(-1) = e^((10 lamda + lamda)) = e^(9 lamda t) rArr t = (1)/(9 lamda)`.
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