The nuclear radius of `._(8)O^(16)` is `3 xx10^(-15) m`. If an atomic mass unit is `1.67 xx 10^(-27) kg`, then the nuclear density is approximately.

Options

A. `2.35 xx 10^17 gm per cm^3`
B. `2.35 xx 10^17 kg per cm^3`
C. `2.35 xx 10^17 gmper metre^3`
D. `2.35 xx 10^17 kg per cm^3`

Answer

B

Explanation

(b) For nucleus of `._8 O^16` ,
Mass `= (16)(1.67 xx 10^-27) kg`
Volume `= (4)/(5) pi R^3`
`(4)/(3) p (3 xx 10^-15)^3 "metre"^3`
`=26 p xx 10^-45 "metre"^3`
`Density = ("mass")/("volume") = (16 xx 67 xx 10^-27 kg)/(36 pi xx 10^-16 "metre"^3)`
=`235 xx 10^17 kg//"metre"^3`.