If the equilibrium constant of the reaction `2HI hArrH_(2) + I_(2)` is `0.25` , then the equilibrium constant of the reaction `H_(2) + I_(2)hArr2HI` would be

If the equilibrium constant of the reaction 2HIhArr H_(2)+I_(2) is 0.25, then the equilibrium constant for the reaction, H_(2)(g)+I_(2)(g)hArr 2HI(g) would be

If the equilibrium constant of the reaction 2HIhArr H_(2)+I_(2) is 0.25, then the equilibrium constant for the reaction, H_(2)(g)+I_(2)(g)hArr 2HI(g) would be

If the equilibrium constant of the reaction 2HI(g)hArrH_2(g)+I_2(g) is 0.25 , the equilibrium constant of the reaction 1/2H_2(g)+1/2I_2(g)hArr HI(g) will be

If the equilibrium constant of the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g) is 0.25 , find the equilibrium constant of the reaction. (1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)

If the equilibrium constant of the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g) is 0.25 , find the equilibrium constant of the reaction. (1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)

The value of equilibrium constant of the reaction, H(g) hArr(1)/(2) H_(2)(g) is 0.8 . The equilibrium constant of the reaction H_(2)(g) + I_(2)(g)hArr2HI(g) will be

If K_e of the reaction, 2HI rarr H_2+ I_2 is 0.25, the equilibrium constant of the reaction H_2+ I_2 rarr 2HI would be :