A lift of very broad - floor is moving vertically upward with a constant retardation equal to 'g'. At an instant a stone is projected from a point on the floor of the lift at angle of elevation 0. Then the trajectory of the stone is:

A very broad elevator is going up vertically with a constant acceleration of 2m//s^(2) . At the instant when its velocity is 4m//s , a ball is projected from the floor of the lift wht as of 4m//s relative to the floor at an elevation of 30^(@) . The time taken by the ball to return the floor is (g=10m//s^(2))

A very broad elevator is going up vertically with constant acceleration of 2 m/s^(2) . At the instant when its velocity is 4 m/s a ball is projected from the floor of the lift with a speed of 4 m/s relative to the floor at an elevation of 30^(@) . The range of ball over the floor of the lift is :

A very broad elevator is going up vertically with a constant acceleration of 2m//s^(2) . At the instant when its velocity is 4m//s a ball is projected form the floor of the lift with a speed of 4m//s relative to the floor at an elevation of 30^(@) . Time taken by the ball to return the floor is (g=10ms^(2))

A very broad elevator is going up vertically with a constant acceleration of 2m//s^(2) . At the instant when its velocity is 4m//s a ball is projected form the floor of the lift with a speed of 4m//s relative to the floor at an elevation of 30^(@) . Time taken by the ball to return the floor is (g=10ms^(2))

A very broad elevator is going up vertically with a constant acceleration of 2m//s^(2) . At the instant when its velocity is 4m//s a ball is projected form the floor of the lift with a speed of 4m//s relative to the floor at an elevation of 30^(@) . Time taken by the ball to return the floor is (g=10ms^(2))

A very broad elevator is going up vertically with a constant acceleration of 2m//s^(2) . At the instant when its velocity is 4m//s a ball is projected form the floor of the lift with a speed of 4m//s relative to the floor at an elevation of 30^(@) . Time taken by the ball to return the floor is (g=10ms^(2))

If an elevator is moving vertically upwards with an acceleration a, the force exerted on the floor by a passenger of mass M is

A lift is moving downwards with an acceleration equal to g . A block of mass m , kept on the floor of the lift of friction coefficient mu , is pulled horizontally . The friction acting on the block is

A lift is moving downwards with an acceleration equal to g . A block of mass m , kept on the floor of the lift of friction coefficient mu , is pulled horizontally . The friction acting on the block is