If `f(x)=ae^(2x)+be^x+cx` satisfies the conditions `f(0)=-1, f\'log(2)=28, int_0^(log4) [f(x)-cx]dx=39/2`, then (A) `a=5, b=6, c=3` (B) `a=5, b=-6, c=0` (C) `a=-5, b=6, c=3` (D) none of these

If f(x) =ae^(2x)+be^(x)+cx , satisfies the conditions f(0)=-1, f'(log 2)=31, int_(0)^(log4) (f(x)-cx)dx=(39)/(2) , then

If f(x)=ae^(2x)+be^(x)+cx satisfies the condition f(0)=ae^(2x)+be^(x)+cx satisfies the condition f(0)=-1, f'(log2)=31,int_(0)^(log4)(f(x)-cx)dx=(39)/(2) , then

Let f(x)=ae^(2x)+be^x+cx , where f(0)=-1, f'(log_e2)=21 and int_0^(log_e4)(f(x)-cx)dx=39/2 then the value of abs(a+b+c) is__________

If f(x)=x^3+bx^2+cx+d and 0< b^2 < c , then

If f(x)=x^3+bx^2+cx+d and 0< b^2 < c , then

If the function f(x)=a x^3+b x^2+11 x-6 satisfies conditions of Rolles theorem in [1,3] and f'(2+1/(sqrt(3)))=0, then values of a and b , respectively, are (A) -3,2 (B) 2,-4 (C) 1,-6 (D) none of these

If the function f(x)=a x^3+b x^2+11 x-6 satisfies conditions of Rolles theorem in [1,3] and f'(2+1/(sqrt(3)))=0, then values of a and b , respectively, are (A) -3,2 (B) 2,-4 (C) 1,-6 (D) none of these

The polynomial f(x)=x^3-bx^2+cx-4 satisfies the conditions of Rolle's theorem for x in [1,2] , f'(4/3) = 0 the order pair (b,c) is

If f(x) = a + bx + cx^2 where a, b, c in R then int_o ^1 f(x)dx