Yellow light emitted from a sodium lamp has a wavelength ( `lambda` ) of ` 580 nm`. Calculate the frequency (v). Wave number and energy of yellow light photon .

Explanation

Frequency `(v) = c/( lambda) = ( 3. 0 xx 10^8)/( 580 xx 10^(-9)`
` = 5 . 17 xx 10^(14) "Hz or" s^(-1)`
Wave no. `overline(v) = 1/(lambda) = 1/( 580 xx 120^(-9)) = 1.724 xx 10^6 m^(-1)`
`E = hv = 6.625 xx 10^(-32) xx 5. 17 xx 10^(14)`
` 34 . 24 xx 10^(-20) J//phot on`.