A 25 watt bulb emits monochromatic yellow light of wavelength of ` 0. 57 mu` m. Calculate the rate of emission of quanta per second .

Explanation

To solve the problem of calculating the rate of emission of quanta (photons) per second from a 25 watt bulb emitting monochromatic yellow light of wavelength \(0.57 \, \mu m\), we can follow these steps:

### Step 1: Understand the Given Information
- Power of the bulb, \( P = 25 \, \text{W} \) (watts)
- Wavelength of light, \( \lambda = 0.57 \, \mu m = 0.57 \times 10^{-6} \, \text{m} \)

### Step 2: Calculate the Total Energy Emitted per Second
Since power is defined as energy per unit time, the total energy emitted by the bulb in one second is equal to its power:
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