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The decreasing order of energy for the...

The decreasing order of energy for the electrons represented by the following sets of quantum number is :
1.`n = 4,l = 0,m = 0,s = +- 1//2`
2.`n = 3,l = 1,m = 1,s = - 1//2`
3.`n = 3,l = 2,m = 0,s = + 1//2`
4.`n = 3,l = 0,m = 0,s = - 1//2`

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Find `( n + l)` for each set
` For (1) ( n + l) = 4 i.e., 4s`
` For (2) ( n + l) = 4 i., e , 3 p`
` For (3) ( n+ l) =5 i.e, 3d`
` For (4) ( n + l) =3 i.e, 3s`
(1) Lower is the value of `( n + l)` lower is energy level .
(2) If `( n +l)` are same then orbital with lower values of ( n) possesses lower energy .
`:.` Decreasing ofer of energy ` 3 gt 1 gt 2 gt 4 .`
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The decrerasing order of energy for the electrons represented by the following sets of quantum number is : 1. n = 4,l = 0,m = 0,s = +- 1//2 2. n = 3,l = 1,m = 1,s = - 1//2 3. n = 3,l = 2,m = 0,s = + 1//2 4. n = 3,l = 0,m = 0,s = - 1//2

Which orbital represents the following set of quantum numbers n =3, l=0, m =0 s = + 1//2

The set of quantum numbers, n = 3, l = 2, m_(l) = 0

The set of quantum numbers, n = 2, l = 2, m_(l) = 0 :

Arrange the electrons represented by the following sets of quantum numbers in decreasing order of energy. (i) n=4, l=0, m_(l)=0, s=+1//2 , (ii) n=3, l=1, m_(l)=1, s=-1//2 (iii) n=3, l=2, m_(l)=0, s=+1//2 , (iv) n=3, l=0, m_(l)=0, s=-1//2

The set of quantum numbers n=3, l=0, m=0, s=-1/2 belongs to the element

From the following sets quantum number state which are possible. Explain why the other are not permitted ? a. n = 0, l = 0, m= 0, s = + 1//2 b. n = 1, l = 0, m= 0, s = - 1//2 c. n = 1, l = 1, m= 0, s = + 1//2 d. n = 1, l = 0, m= +1, s = + 1//2 e. n = 0, l = 1, m= -1, s = - 1//2 f. n = 2, l = 2, m= 0, s = - 1//2 g. n = 2, l = 1, m= 0, s = - 1//2

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